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Problem 526 from Connelly's corpus: Ha, Hb, N


Problem

Given a point Ha, a point Hb and a point N, construct the triangle ABC.

Status

ArgoTriCS says that the problem is locus dependent.

Illustration

Figure of construction

Solution


  1. Using the point Hb and the point N, construct a circle k(N,Ma) (rule W06);

    % NDG: points Hb and N are not the same

  2. Choose freely a point Ha on the circle k(N,Ma) (rule WOncircle)

  3. Using the point Ha and the point Hb, construct a line m(HaHb) (rule W14);

    % DET: points Ha and Hb are not the same

  4. Using the circle k(N,Ma) and the line m(HaHb), construct a point Mc and a point Ec (rule W04);

    % NDG: line m(HaHb) and circle k(N,Ma) intersect

  5. Choose freely a point A on the circle k(Mc,A) (rule WOncircle)

  6. Using the point A and the point Mc, construct a point B (rule W01);

  7. Using the point A and the point Ha, construct a line ha (rule W02);

    % DET: points A and Ha are not the same

  8. Using the point Hb and the point B, construct a line hb (rule W02);

    % DET: points Hb and B are not the same

  9. Using the line ha and the line hb, construct a point H (rule W03);

    % NDG: lines ha and hb are not parallel

    % DET: lines ha and hb are not the same

  10. Using the point N and the point H, construct a point G (rule W01);

  11. Using the point Mc and the point G, construct a point C (rule W01);

animation
Construction in GCLC language

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