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Problem 483 from Connelly's corpus: Ec, Mb, N


Problem

Given a point Ec, a point Mb and a point N, construct the triangle ABC.

Status

ArgoTriCS says that the problem is locus dependent.

Illustration

Figure of construction

Solution


  1. Using the point Mb and the point N, construct a circle k(N,Ma) (rule W06);

    % NDG: points Mb and N are not the same

  2. Choose freely a point Ec on the circle k(N,Ma) (rule WOncircle)

  3. Using the point Ec and the point N, construct a line m(HbHa) (rule W02);

    % DET: points Ec and N are not the same

  4. Using the circle k(N,Ma), the line m(HbHa), the point N and the point Ec, construct a point Mc (rule W05a);

    % NDG: line m(HbHa) and circle k(N,Ma) intersect

    % DET: points Ec and Mc must be different

  5. Choose freely a point A (rule free)

  6. Using the point A and the point Mb, construct a point C (rule W01);

  7. Using the point A and the point Mc, construct a point B (rule W01);

animation
Construction in GCLC language

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