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Problem 397 from Connelly's corpus: Eb, Mc, N


Problem

Given a point Eb, a point Mc and a point N, construct the triangle ABC.

Status

ArgoTriCS says that the problem is locus dependent.

Illustration

Figure of construction

Solution


  1. Using the point Mc and the point N, construct a circle k(N,Ma) (rule W06);

    % NDG: points Mc and N are not the same

  2. Choose freely a point Eb on the circle k(N,Ma) (rule WOncircle)

  3. Using the point Eb and the point N, construct a line m(HaHc) (rule W02);

    % DET: points Eb and N are not the same

  4. Using the circle k(N,Ma), the line m(HaHc), the point N and the point Eb, construct a point Mb (rule W05a);

    % NDG: line m(HaHc) and circle k(N,Ma) intersect

    % DET: points Eb and Mb must be different

  5. Choose freely a point A (rule free)

  6. Using the point A and the point Mc, construct a point B (rule W01);

  7. Using the point A and the point Mb, construct a point C (rule W01);

animation
Construction in GCLC language

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