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Problem 393 from Connelly's corpus: Eb, Mb, O


Problem

Given a point Eb, a point Mb and a point O, construct the triangle ABC.

Status

ArgoTriCS says that the problem is solvable.

Illustration

Figure of construction

Solution


  1. Using the point Eb and the point Mb, construct a line m(HaHc) (rule W02);

    % DET: points Eb and Mb are not the same

  2. Using the point Mb and the point O, construct a line mb (rule W02);

    % DET: points Mb and O are not the same

  3. Using the point Mb and the line mb, construct a line b (rule W10a);

  4. Using the point Eb and the point Mb, construct a line m(EbMb) (rule W14);

    % DET: points Eb and Mb are not the same

  5. Using the line m(EbMb) and the line m(HaHc), construct a point N (rule W03);

    % NDG: lines m(EbMb) and m(HaHc) are not parallel

    % DET: lines m(EbMb) and m(HaHc) are not the same

  6. Using the point N and the point O, construct a point G (rule W01);

  7. Using the point Mb and the point G, construct a point B (rule W01);

  8. Using the point B and the point O, construct a circle k(O,C) (rule W06);

    % NDG: points B and O are not the same

  9. Using the circle k(O,C) and the line b, construct a point C and a point A (rule W04);

    % NDG: line b and circle k(O,C) intersect

animation
Construction in GCLC language

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