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Problem 391 from Connelly's corpus: Mc, Eb, Mb


Problem

Given a point Mc, a point Eb and a point Mb, construct the triangle ABC.

Status

ArgoTriCS says that the problem is locus dependent.

Illustration

Figure of construction

Solution


  1. Using the point Eb and the point Mb, construct a line m(HaHc) (rule W02);

    % DET: points Eb and Mb are not the same

  2. Using the point Eb and the point Mb, construct a line m(EbMb) (rule W14);

    % DET: points Eb and Mb are not the same

  3. Using the line m(EbMb) and the line m(HaHc), construct a point N (rule W03);

    % NDG: lines m(EbMb) and m(HaHc) are not parallel

    % DET: lines m(EbMb) and m(HaHc) are not the same

  4. Using the point Eb and the point N, construct a circle k(N,Ma) (rule W06);

    % NDG: points Eb and N are not the same

  5. Choose freely a point Mc on the circle k(N,Ma) (rule WOncircle)

  6. Choose freely a point A (rule free)

  7. Using the point A and the point Mc, construct a point B (rule W01);

  8. Using the point A and the point Mb, construct a point C (rule W01);

animation
Construction in GCLC language

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