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Problem 360 from Connelly's corpus: Eb, Hb, Mb


Problem

Given a point Eb, a point Hb and a point Mb, construct the triangle ABC.

Status

ArgoTriCS says that the problem is locus dependent.

Illustration

Figure of construction

Solution


  1. Using the point Hb and the point Mb, construct a line b (rule W02);

    % DET: points Hb and Mb are not the same

  2. Using the point Hb and the line b, construct a line hb (rule W10b);

  3. Choose freely a point Eb on the line hb (rule WOnline2)

  4. Using the point Eb and the point Mb, construct a line m(HaHc) (rule W02);

    % DET: points Eb and Mb are not the same

  5. Using the point Eb and the point Hb, construct a line m(EbHb) (rule W14);

    % DET: points Eb and Hb are not the same

  6. Using the line m(EbHb) and the line m(HaHc), construct a point N (rule W03);

    % NDG: lines m(EbHb) and m(HaHc) are not parallel

    % DET: lines m(EbHb) and m(HaHc) are not the same

  7. Using the point Eb and the point N, construct a circle k(N,Ma) (rule W06);

    % NDG: points Eb and N are not the same

  8. Choose freely a point A on the line b (rule WOnline1)

  9. Using the point A and the point Mb, construct a point C (rule W01);

  10. Using the point A and the point Mb, construct a circle k(Mb,C) (rule W06);

    % NDG: points A and Mb are not the same

  11. Using the circle k(N,Ma) and the circle k(Mb,C), construct a point Ha and a point Hc (rule W07);

    % NDG: circles k(N,Ma) and k(Mb,C) intersect

    % DET: circles k(N,Ma) and k(Mb,C) are not the same

  12. Using the point A and the point Ha, construct a line ha (rule W02);

    % DET: points A and Ha are not the same

  13. Using the line hb and the line ha, construct a point H (rule W03);

    % NDG: lines hb and ha are not parallel

    % DET: lines hb and ha are not the same

  14. Using the point Eb and the point H, construct a point B (rule W01);

animation
Construction in GCLC language

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