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Problem 315 from Connelly's corpus: Eb, Ec, Mc


Problem

Given a point Eb, a point Ec and a point Mc, construct the triangle ABC.

Status

ArgoTriCS says that the problem is locus dependent.

Illustration

Figure of construction

Solution


  1. Using the point Ec and the point Mc, construct a line m(HbHa) (rule W02);

    % DET: points Ec and Mc are not the same

  2. Using the point Ec and the point Mc, construct a line m(EcMc) (rule W14);

    % DET: points Ec and Mc are not the same

  3. Using the line m(EcMc) and the line m(HbHa), construct a point N (rule W03);

    % NDG: lines m(EcMc) and m(HbHa) are not parallel

    % DET: lines m(EcMc) and m(HbHa) are not the same

  4. Using the point Ec and the point N, construct a circle k(N,Ma) (rule W06);

    % NDG: points Ec and N are not the same

  5. Choose freely a point Eb on the circle k(N,Ma) (rule WOncircle)

  6. Using the point Eb and the point N, construct a line m(HaHc) (rule W02);

    % DET: points Eb and N are not the same

  7. Using the circle k(N,Ma), the line m(HaHc), the point N and the point Eb, construct a point Mb (rule W05a);

    % NDG: line m(HaHc) and circle k(N,Ma) intersect

    % DET: points Eb and Mb must be different

  8. Choose freely a point A (rule free)

  9. Using the point A and the point Mc, construct a point B (rule W01);

  10. Using the point A and the point Mb, construct a point C (rule W01);

animation
Construction in GCLC language

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