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Problem 287 from Connelly's corpus: Ea, Mb, N


Problem

Given a point Ea, a point Mb and a point N, construct the triangle ABC.

Status

ArgoTriCS says that the problem is locus dependent.

Illustration

Figure of construction

Solution


  1. Using the point Mb and the point N, construct a circle k(N,Ma) (rule W06);

    % NDG: points Mb and N are not the same

  2. Choose freely a point Ea on the circle k(N,Ma) (rule WOncircle)

  3. Using the point Ea and the point N, construct a line m(HbHc) (rule W02);

    % DET: points Ea and N are not the same

  4. Using the circle k(N,Ma), the line m(HbHc), the point N and the point Ea, construct a point Ma (rule W05a);

    % NDG: line m(HbHc) and circle k(N,Ma) intersect

    % DET: points Ea and Ma must be different

  5. Choose freely a point A (rule free)

  6. Using the point A and the point Mb, construct a point C (rule W01);

  7. Using the point A and the point Ma, construct a point G (rule W01);

  8. Using the point Mb and the point G, construct a point B (rule W01);

animation
Construction in GCLC language

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