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Problem 281 from Connelly's corpus: Ea, Ma, N


Problem

Given a point Ea, a point Ma and a point N, construct the triangle ABC.

Status

ArgoTriCS says that the problem is redundant.

Illustration

Figure of construction

Solution


  1. Using the point Ma and the point N, construct a line m(HbHc) (rule W02);

    % DET: points Ma and N are not the same

  2. Using the point Ma and the point N, construct a circle k(N,Ma) (rule W06);

    % NDG: points Ma and N are not the same

  3. Using the circle k(N,Ma), the line m(HbHc), the point N and the point Ma, construct a point Ea (rule W05a);

    % NDG: line m(HbHc) and circle k(N,Ma) intersect

    % DET: points Ma and Ea must be different

  4. Choose freely a point A (rule free)

  5. Using the point A and the point Ma, construct a point G (rule W01);

  6. Using the point N and the point G, construct a point O (rule W01);

  7. Using the point A and the point Ea, construct a line ha (rule W02);

    % DET: points A and Ea are not the same

  8. Using the circle k(N,Ma), the line ha, the point N and the point Ea, construct a point Ha (rule W05);

    % NDG: line ha and circle k(N,Ma) intersect

    % DET: points Ea and Ha must be different

  9. Using the point Ha and the point Ma, construct a line a (rule W02);

    % DET: points Ha and Ma are not the same

  10. Using the point A and the point O, construct a circle k(O,C) (rule W06);

    % NDG: points A and O are not the same

  11. Using the circle k(O,C) and the line a, construct a point C and a point B (rule W04);

    % NDG: line a and circle k(O,C) intersect

animation
Construction in GCLC language

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