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Problem 196 from Connelly's corpus: Ea, Eb, Mc


Problem

Given a point Ea, a point Eb and a point Mc, construct the triangle ABC.

Status

ArgoTriCS says that the problem is solvable.

Illustration

Figure of construction

Solution


  1. Using the point Eb and the point Mc, construct a line m(BHa) (rule W02);

    % DET: points Eb and Mc are not the same

  2. Using the point Ea and the point Eb, construct a line m(EaEb) (rule W14);

    % DET: points Ea and Eb are not the same

  3. Using the point Ea and the point Mc, construct a line m(EaMc) (rule W14);

    % DET: points Ea and Mc are not the same

  4. Using the line m(EaMc) and the line m(EaEb), construct a point N (rule W03);

    % NDG: lines m(EaMc) and m(EaEb) are not parallel

    % DET: lines m(EaMc) and m(EaEb) are not the same

  5. Using the point Ea and the point N, construct a circle k(N,Ma) (rule W06);

    % NDG: points Ea and N are not the same

  6. Using the point Ea and the line m(BHa), construct a line ha (rule W16);

  7. Using the circle k(N,Ma), the line ha, the point N and the point Ea, construct a point Ha (rule W05);

    % NDG: line ha and circle k(N,Ma) intersect

    % DET: points Ea and Ha must be different

  8. Using the point Ha and the point Eb, construct a circle k(Eb,B) (rule W06);

    % NDG: points Ha and Eb are not the same

  9. Using the circle k(Eb,B), the line ha, the point Eb and the point Ha, construct a point H (rule W05);

    % NDG: line ha and circle k(Eb,B) intersect

    % DET: points Ha and H must be different

  10. Using the point H and the point Ea, construct a point A (rule W01);

  11. Using the point Eb and the point H, construct a point B (rule W01);

  12. Using the point N and the point H, construct a point G (rule W01);

  13. Using the point Mc and the point G, construct a point C (rule W01);

animation
Construction in GCLC language

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