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Problem 138 from Connelly's corpus: C, Ea, Mb


Problem

Given a point C, a point Ea and a point Mb, construct the triangle ABC.

Status

ArgoTriCS says that the problem is solvable.

Illustration

Figure of construction

Solution


  1. Using the point C and the point Mb, construct a point A (rule W01);

  2. Using the point Ea and the point A, construct a point H (rule W01);

  3. Using the point C and the point H, construct a line hc (rule W02);

    % DET: points C and H are not the same

  4. Using the point Ea and the point A, construct a line ha (rule W02);

    % DET: points Ea and A are not the same

  5. Using the point C and the point Mb, construct a circle k(Mb,C) (rule W06);

    % NDG: points C and Mb are not the same

  6. Using the circle k(Mb,C), the line hc, the point Mb and the point C, construct a point Hc (rule W05);

    % NDG: line hc and circle k(Mb,C) intersect

    % DET: points C and Hc must be different

  7. Using the point Hc and the point A, construct a line c (rule W02);

    % DET: points Hc and A are not the same

  8. Using the circle k(Mb,C), the line ha, the point Mb and the point A, construct a point Ha (rule W05);

    % NDG: line ha and circle k(Mb,C) intersect

    % DET: points A and Ha must be different

  9. Using the point Ha and the point C, construct a line a (rule W02);

    % DET: points Ha and C are not the same

  10. Using the line c and the line a, construct a point B (rule W03);

    % NDG: lines c and a are not parallel

    % DET: lines c and a are not the same

animation
Construction in GCLC language

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