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Problem 124 from Connelly's corpus: B, Mc, N


Problem

Given a point B, a point Mc and a point N, construct the triangle ABC.

Status

ArgoTriCS says that the problem is solvable.

Illustration

Figure of construction

Solution


  1. Using the point B and the point Mc, construct a point A (rule W01);

  2. Using the point B and the point Mc, construct a line c (rule W02);

    % DET: points B and Mc are not the same

  3. Using the point Mc and the point N, construct a line m(HbHa) (rule W02);

    % DET: points Mc and N are not the same

  4. Using the point B and the point Mc, construct a circle k(Mc,A) (rule W06);

    % NDG: points B and Mc are not the same

  5. Using the point Mc and the point N, construct a circle k(N,Ma) (rule W06);

    % NDG: points Mc and N are not the same

  6. Using the circle k(N,Ma), the line c, the point N and the point Mc, construct a point Hc (rule W05);

    % NDG: line c and circle k(N,Ma) intersect

    % DET: points Mc and Hc must be different

  7. Using the circle k(N,Ma), the line m(HbHa), the point N and the point Mc, construct a point Ec (rule W05a);

    % NDG: line m(HbHa) and circle k(N,Ma) intersect

    % DET: points Mc and Ec must be different

  8. Using the point Ec and the point Hc, construct a line hc (rule W02);

    % DET: points Ec and Hc are not the same

  9. Using the circle k(Mc,A) and the circle k(N,Ma), construct a point Hb and a point Ha (rule W07);

    % NDG: circles k(Mc,A) and k(N,Ma) intersect

    % DET: circles k(Mc,A) and k(N,Ma) are not the same

  10. Using the point B and the point Hb, construct a line hb (rule W02);

    % DET: points B and Hb are not the same

  11. Using the line hc and the line hb, construct a point H (rule W03);

    % NDG: lines hc and hb are not parallel

    % DET: lines hc and hb are not the same

  12. Using the point N and the point H, construct a point G (rule W01);

  13. Using the point Mc and the point G, construct a point C (rule W01);

animation
Construction in GCLC language

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