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Problem 459 from Wernick's corpus: Mc, Hb, Tb


Problem

Given a point Mc, a point Hb and a point Tb, construct the triangle ABC.

Status

ArgoTriCS says that the problem is solvable.

Illustration

Figure of construction

Solution


  1. Using the point Hb and the point Tb, construct a line b (rule W02);

    % DET: points Hb and Tb are not the same

  2. Using the point Hb and the point Mc, construct a circle k(Mc,A) (rule W06);

    % NDG: points Hb and Mc are not the same

  3. Using the circle k(Mc,A), the line b, the point Mc and the point Hb, construct a point A (rule W05);

    % NDG: line b and circle k(Mc,A) intersect

    % DET: points Hb and A must be different

  4. Using the point A and the point Mc, construct a point B (rule W01);

  5. Using the point Mc and the point A, construct a line c (rule W02);

    % DET: points Mc and A are not the same

  6. Using the point Tb and the line c, construct a circle k(Tb,foot[Tb,c]) (rule W11);

    % NDG: point Tb is not incident to the line c

  7. Using the circle k(Tb,foot[Tb,c]), the point B, the point Tb and the line c, construct a line a (rule W13);

    % NDG: point B is outside the circle k(Tb,foot[Tb,c])

  8. Using the line a and the line b, construct a point C (rule W03);

    % NDG: lines a and b are not parallel

    % DET: lines a and b are not the same

animation
Construction in GCLC language

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