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Problem 457 from Wernick's corpus: Mc, Hb, H


Problem

Given a point Mc, a point Hb and a point H, construct the triangle ABC.

Status

ArgoTriCS says that the problem is solvable.

Illustration

Figure of construction

Solution


  1. Using the point Hb and the point H, construct a line hb (rule W02);

    % DET: points Hb and H are not the same

  2. Using the point Hb and the point Mc, construct a circle k(Mc,A) (rule W06);

    % NDG: points Hb and Mc are not the same

  3. Using the circle k(Mc,A), the line hb, the point Mc and the point Hb, construct a point B (rule W05);

    % NDG: line hb and circle k(Mc,A) intersect

    % DET: points Hb and B must be different

  4. Using the point B and the point Mc, construct a point A (rule W01);

  5. Using the point Hb and the point A, construct a line b (rule W02);

    % DET: points Hb and A are not the same

  6. Using the point H and the point A, construct a line ha (rule W02);

    % DET: points H and A are not the same

  7. Using the circle k(Mc,A), the line ha, the point Mc and the point A, construct a point Ha (rule W05);

    % NDG: line ha and circle k(Mc,A) intersect

    % DET: points A and Ha must be different

  8. Using the point B and the point Ha, construct a line a (rule W02);

    % DET: points B and Ha are not the same

  9. Using the line b and the line a, construct a point C (rule W03);

    % NDG: lines b and a are not parallel

    % DET: lines b and a are not the same

animation
Construction in GCLC language

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