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Problem 452 from Wernick's corpus: Mc, Ha, Ta


Problem

Given a point Mc, a point Ha and a point Ta, construct the triangle ABC.

Status

ArgoTriCS says that the problem is solvable.

Illustration

Figure of construction

Solution


  1. Using the point Ha and the point Ta, construct a line a (rule W02);

    % DET: points Ha and Ta are not the same

  2. Using the point Ha and the point Mc, construct a circle k(Mc,A) (rule W06);

    % NDG: points Ha and Mc are not the same

  3. Using the circle k(Mc,A), the line a, the point Mc and the point Ha, construct a point B (rule W05);

    % NDG: line a and circle k(Mc,A) intersect

    % DET: points Ha and B must be different

  4. Using the point B and the point Mc, construct a point A (rule W01);

  5. Using the point Mc and the point B, construct a line c (rule W02);

    % DET: points Mc and B are not the same

  6. Using the point Ta and the line c, construct a circle k(Ta,foot[Ta,c]) (rule W11);

    % NDG: point Ta is not incident to the line c

  7. Using the circle k(Ta,foot[Ta,c]), the point A, the point Ta and the line c, construct a line b (rule W13);

    % NDG: point A is outside the circle k(Ta,foot[Ta,c])

  8. Using the line b and the line a, construct a point C (rule W03);

    % NDG: lines b and a are not parallel

    % DET: lines b and a are not the same

animation
Construction in GCLC language

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