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Problem 405 from Wernick's corpus: Mb, G, Ha


Problem

Given a point Mb, a point G and a point Ha, construct the triangle ABC.

Status

ArgoTriCS says that the problem is solvable.

Illustration

Figure of construction

Solution


  1. Using the point Mb and the point G, construct a point B (rule W01);

  2. Using the point Ha and the point B, construct a line a (rule W02);

    % DET: points Ha and B are not the same

  3. Using the point Ha and the point Mb, construct a circle k(Mb,C) (rule W06);

    % NDG: points Ha and Mb are not the same

  4. Using the circle k(Mb,C), the line a, the point Mb and the point Ha, construct a point C (rule W05);

    % NDG: line a and circle k(Mb,C) intersect

    % DET: points Ha and C must be different

  5. Using the point C and the point Mb, construct a point A (rule W01);

animation
Construction in GCLC language

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