Back to the list of problems

Problem 397 from Wernick's corpus: Mb, Mc, Ha


Problem

Given a point Mb, a point Mc and a point Ha, construct the triangle ABC.

Status

ArgoTriCS says that the problem is solvable.

Illustration

Figure of construction

Solution


  1. Using the point Ha and the point Mb, construct a circle k(Mb,C) (rule W06);

    % NDG: points Ha and Mb are not the same

  2. Using the point Ha and the point Mc, construct a circle k(Mc,A) (rule W06);

    % NDG: points Ha and Mc are not the same

  3. Using the circle k(Mb,C), the circle k(Mc,A), the point Ha, the point Mb and the point Mc, construct a point A (rule W08);

    % NDG: circles k(Mb,C) and k(Mc,A) intersect

    % DET: circles k(Mb,C) and k(Mc,A) are not the same points Ha and A must be different

  4. Using the point A and the point Mb, construct a point C (rule W01);

  5. Using the point Mc and the point A, construct a point B (rule W01);

animation
Construction in GCLC language

Back to the list of problems