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Problem 240 from Wernick's corpus: C, G, Hb


Problem

Given a point C, a point G and a point Hb, construct the triangle ABC.

Status

ArgoTriCS says that the problem is solvable.

Illustration

Figure of construction

Solution


  1. Using the point C and the point G, construct a point Mc (rule W01);

  2. Using the point C and the point Hb, construct a line b (rule W02);

    % DET: points C and Hb are not the same

  3. Using the point Hb and the point Mc, construct a circle k(Mc,A) (rule W06);

    % NDG: points Hb and Mc are not the same

  4. Using the circle k(Mc,A), the line b, the point Mc and the point Hb, construct a point A (rule W05);

    % NDG: line b and circle k(Mc,A) intersect

    % DET: points Hb and A must be different

  5. Using the point G and the point A, construct a point Ma (rule W01);

  6. Using the point C and the point Ma, construct a point B (rule W01);

animation
Construction in GCLC language

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