#include <stdio.h>

/* primer: f(3764431), ocekivani rezultat 30705443010
  resenje potproblema: f(376443) = 307064430
  resenje problema f(3764431) = (f(376443)*10+1)*10
*/

unsigned umetni0(unsigned n){
	unsigned res;
	if(n==0)
		return 0;
	res = umetni0(n/10)*10+n%10;
	if(n%2==1)
		res*=10;
	return res;
}

int main(){
	unsigned n;
	scanf("%u", &n);
	printf("%u\n", umetni0(n));
	return 0;
}